What is the angle between the reflected and transmitted rays?

25.September, 2009

A beam of light is incident upon a flat piece of glass (n = 1.50) at an angle of incidence of 30°. Part of the beam is transmitted and part is reflected. What is the angle between the reflected and transmitted rays?

?(reflection) = 30°

n(1)sin ?(1) = n(2)sin ?(2)
(1.00)sin 30° = (1.50)sin ?(2)
?(2) = 19.5°

angle between rays = 180° – (30° + 19.5°) = 130.5°

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2 Meinungen für “What is the angle between the reflected and transmitted rays?”

  1. Joshua K sagt:
    25.September, 2009 um 10:53 am

    ?(reflection) = 30°

    n(1)sin ?(1) = n(2)sin ?(2)
    (1.00)sin 30° = (1.50)sin ?(2)
    ?(2) = 19.5°

    angle between rays = 180° – (30° + 19.5°) = 130.5°
    References :

  2. daniel b sagt:
    25.September, 2009 um 11:20 am

    both the same angle
    References :

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