Jimmy has caught two fish in Yellow Creek. He has tied the line holding the 4.90 kg steelhead trout to the tail of the 2.35 kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 77.3 N. What is the tension of the rope connecting the steel trout and carp?

The acceleration of the two fish is first found as the difference between the total weight and the lifting force = total mass x accel;

F – (mg + Mg) = (m+M)a

77.3 – (4.9+2.35)(9.8) = (4.9+2.35)a

a = 6.25/7.25 = .86 m/ss

The tension in the rope is then found by writing the forces just on the trout (bottom fish);

T – mg = ma

T = m(g+a)

= (4.9)(9.8+.86)

= 52.2 N

1 Meinung für “What is the tension of the rope connecting the steel trout and carp?”

  1. debydete sagt:

    The acceleration of the two fish is first found as the difference between the total weight and the lifting force = total mass x accel;

    F – (mg + Mg) = (m+M)a

    77.3 – (4.9+2.35)(9.8) = (4.9+2.35)a

    a = 6.25/7.25 = .86 m/ss

    The tension in the rope is then found by writing the forces just on the trout (bottom fish);

    T – mg = ma

    T = m(g+a)

    = (4.9)(9.8+.86)

    = 52.2 N
    References :

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