Gone Fishin’!

We want to put our old refrigerator down in the basement, but the doors are too small. Anybody experienced in this know a way to do this?

You will have to remove door. . .woodwork and widen the doorway if possible. Might be a good time to remodel that small doorway first.

We want to put our old refrigerator down in the basement, but the doors are too small. Anybody experienced in this know a way to do this?

Refrigerators are typically 25" deep, so turn the refrigerator sideways to go through the door. You may have to remove the doors, both on the fridge and the wall.

If an angling business was to be setting up, how much money would you estimate to have been spent on the products from wholesalers ?

To keep costs down you could dropship.

Basically, you act as a front for some other business, you receive an order, and then place that order through your supplier, your supplier then delivers your customers order to their door, and in return you take a small markup.

Its a clever way of doing business with low investment - you then spend your money on building a brand

If an angling business was to be setting up, how much money would you estimate to have been spent on the products from wholesalers ?

To keep costs down you could dropship.

Basically, you act as a front for some other business, you receive an order, and then place that order through your supplier, your supplier then delivers your customers order to their door, and in return you take a small markup.

Its a clever way of doing business with low investment - you then spend your money on building a brand

My husband needs to cut a notch at an angle out of two hand rails to fit around the corner of the posts on the porch. The posts are turned and the rail will meet the posts at the corners. So he has to get the hand rail which is coming up to the post at an angle to fit around that 90 degree corner snugly.
Any suggestions?

use cardboard to make a template and then use a scrap piece of wood same thickness as rail and work with it til you get the right angle and then use it to cut out your rails.

As an example:

Simple amines, molecules containing a nitrogen, are hybridized approximately sp3 at nitrogen and thus are pyramidal. The bond angles are close to the tetrahedral angle of 109.5, but, of course, cannot be exactly the tetrahedral angle. Why?

Understanding the logic and not just the facts behind it would be really helpful. Thanks in advance.

Well, NH3 for example is asymmetric, unlike CH4 - it has a lone pair of electrons instead of an atom as the fourth "group" sticking off of the central atom. Electrons that are present as lone pairs take up slightly more space because they are not confined in a bond, so they "push" the three H-N-H bonds down a little, causing the N-H angles to decrease slightly. CH4, on the other hand, also has four "groups" sticking off of the central atom, but they’re all the same - single bonded H atoms. Since each of the C-H bonds is identical*, they take up exactly the same amount of space and therefore the bond angles are identical as well.

* for this application, this is true, but if you get into molecular orbital theory in more detail in organic chemistry, you will see that the four C-H bonds are actually NOT exactly the same. Or so the current theory says!

An archer wishes to shoot an arrow at a target at eye level a distance of 42.5 m away. If the initial speed imparted to the arrow is 75.0 m/s, what angle should the arrow make with the horizontal as it is being shot?

Please let me know how to solve this, thanks!

It depends a great deal on the seemingly unimportant variables you did not include in the equation. What is the amount of force applied to the arrow; direction and speed of wind, if any; physical weight of the arrow; dynamic balance of the arrow (how far from front or rear is the actual point of balance)? There are other variables as well, and they must all be included in the equation.

The answer to the question, as it is now worded, is "somewhere between 0 and 90 degrees above horizontal". It might be 1/2 a degree, and it might be 40 degrees, it might be 0 degrees — depending on the variables which are not included in the formulation of the question.

A beam of light is incident upon a flat piece of glass (n = 1.50) at an angle of incidence of 30°. Part of the beam is transmitted and part is reflected. What is the angle between the reflected and transmitted rays?

?(reflection) = 30°

n(1)sin ?(1) = n(2)sin ?(2)
(1.00)sin 30° = (1.50)sin ?(2)
?(2) = 19.5°

angle between rays = 180° - (30° + 19.5°) = 130.5°

I am going to try one of there lakes tomorow not sure which to go for. Not after massive fish

Have you cleared it with the Milton Keynes Navy?
The carp protection fleet is awesome.
Their gunship can fire an Arlesey bomb over 300 metres and I did hear that their ground station long gun fired one right back into Arlesey Lake 15 miles away at the end of May to celebrate Richard Walker’s birthday. He invented it there to get fish out of the deep trenches which required a long cast and an aerodynamic weight to get the distance. Local hero for anglers.
Willen Lake is good, only two minutes drive off the M1 and the National Express temporary bus station isn’t far away which has a good car park, OK if the ones around Willen are clogged up, and the walk through Cambell Park to the lake is quite scenic.
The X5 Oxford-Bedford-Cambridge bus stops there as well. Signposted from the motorway exit with oblong yellow or white signs for National Express, and a snack bar available day and night.
Quite handy. Easy enough to pull into the car park at two in the morning, grab a take-out coffee and bacon butty or two and drive back to the lake with them.
Fishing is OK. Good days and bad but a quite pleasant and attractive place to be. Better on wet days which keep the watersports people and holidaymakers away. It’s bit of a resort these days for local families. Bit of a walk to the quieter spots but worth it. Some good carp in the north lake and massive pike everywhere.
Another good venue not too far away is the Tring Resevoirs. Very nice. Had some good times there. Lovely cafe, bit pricey but good food and popular for Sunday lunches. Best away from traditional meal times to avoid the waiting. The fishing is good in Startops reservoir, big bream, carp, pike, etc. The others are OK-ish.
The Anglers Pub on the bridge is good too.
http://www.mkaa.co.uk/320_lakes.htm
http://www.tringreservoirs.com/

How does the Angle of Attack affect lift in terms of of the equation F=ma?

F= lift
m= mass of air diverted downwards
a= the change in velocity of the air being diverted downwards

In other words, does increasing the AoA increase the amount of air being diverted down? or does it speed up the vertical velocity of the air?

I know that increasing the AoA results in more lift (until you hit the stall angle), but I don’t understand why.
Skyhawk, I am aware of the "real" lift equation, and the AoA vs. lift coefficient curve, but you’re not really answering my question.
Drewpie,

Yep, your answer is what I’m looking for. You mentioned that increasing the AoA will increase the velocity of airflow on the top of the wing. What I’ve been trying to ask is why this happens. How does tilting a wing increase the velocity of air ontop of a wing?

I think you are really looking for:
Yes increasing AOA increases the velocity on the topside of the airfoil. It does the same thing as increasing the chamber but is less efficient at it.

It does NOT force any air down. You can thinking of it as "sucking a plane upward". There is NO magic column of air pushing the plane up (unless you are talking about the harrier).

And yes you can make a plane fly without any chamber in the wing. Using only angle of attack to create lift. I don’t know if any real planes have been made to fly this way because of the lack of efficiency and control but the IFO you can buy does this little neat trick in a R/C model.

http://www.flyifo.com/htmlpages/tifo.html