I have a Canon Rebel XT camera and i wanted to get a wide angle lens, i was just wondering what is the difference between the converter and the full wide-angle lens? Ive seen the wide-angle lenses but it seems like there so exspensive… Is there a difference in quality on a converter? And is it better to get a converter lens or the actual full lens? Maybe some good sites to buy these lenses??

A wide angle lens replaces (temporarily) your standard lens, while a wide angle lens converter screws onto the front of your existing lens (it requires that you get the right one based on the filter thread at the front of your lens).

If it were that simple we’d all be using wide angle converters and there would be no market for wide angle lenses, however there is, so why? Well, the reason is very simple, every wide angle converter I’ve seen causes horrendous chromatic aberration. That’s to say that the colours of light are not focused properly and so especially at the extremes of the image and at edges within the photo you can see the colours separating. You can use this to artistic effect, but with little control, it’s more often just plain annoying and makes your photos valueless!

Even the best wide angle lens is going to display some chromatic aberration, but far far far less than a wide angle converter will.


It’s an abbreviation of the word swimming

batik madrim mbalelo merupakan episode ke-2 dari rangkaian serial angling dharma. semoga berkenan bagi temen2 youtuber semua!

Duration : 0:7:1

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I have a wall angle of 91 degrees. I would like to miter and bevel some shelves. Just mitering at 45.5 degrees and then beveling the edges changes the overall 91 degrees desired. How do I figure out what angle to miter at so that I can bevel the cut at a 15 degree angle and still come out with a total wall angle of 91 degrees?

If you want a tight fit, put the first board into the corner uncut and then cope the shape of that board on the connecting board.

This is a question in my lab manual. My angle was 20 degrees

For each of the angles used in this experiment, is there are second angle for which the range would be the same? Derive an equation that proves your hypothesis.

Thanks for the help.

For a constant launch velocity and a trajectory whose launch and impact elevations are the same, the maximum range occurs at 45 deg elevation. The range decreases continuously from maximum to zero as the elevation goes from 45 to 0 or from 45 to 90. Thus if your first angle is < 45, there must be another angle > 45 that results in the same range. In fact the two angles are complementary, thus your 2nd angle = 70 deg.
The formula needed, R = v0^2*sin(2theta)/g is derived in the ref. For maximum range R, sin(2theta) must be = 1, so theta = 45 deg.

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Filmmaker: Mike Phillips

Duration : 0:1:46

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Well, my project is to make a glasses for the coaches to measure their players’ degree of angle when they throw the ball. The glasses will have a range where it is most ideal for the players to throw their ball. So can anyone help to give the best angle for throwing the basketball so I can include an angle range? Thank you.

just practice your form

Hello,

I’m a little stuck on a math problem and can’t find the answer anywhere. It would really help if I knew what it meant when one angle is the supplement of another, haha. I have to find x in this problem: The largest exterior angle has the measure x + 8, and the smallest interior angle is the supplement of that angle. It is refering to a triangle.

Please don’t tell me the answer! However If I could get the equation that would be a great help. Thank you!

A supplement is something you add to another number to make 180 degrees. Hopefully it gave you something on the interior angle, because you’d have to add that to the x+8, then set it equal to 180 degrees, then solve for X.

If it doesn’t, then I’d assume that the interior angle is X.

Good luck!

Angling Times Legends

07.September, 2009

A run down of Angling Times’ Xmas Special Legends edition. Here are the top 15.

Duration : 0:16:39

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Basically, I just need tips for solving angles in circles that are inscribed or central angles (yes, bad wording.) I just kinda miss the "big" picture sometimes. I get the concepts of the theorems, but actually finding the angles is a pretty big challenge for me sometimes.

You can go on:

http://www.mathwarehouse.com/geometry/circle/inscribed-angle.html

Here are my tips that I use:
Formula for inscribed angle
If you know the length of the minor arc and radius, the inscribed angle is:

where:
L is the length of the minor (shortest) arc AB
R is the radius of the circle
? is Pi, approximately 3.142

Arcs and Chords
The two points A and B can be isolated points, or they could be the end points of an arc or chord. When they are the end points of an arc, the angle is sometimes called the peripheral angle of the arc.
Central Angle
A similar concept is the central angle. This is the angle subtended at the center of the circle by the two given points.

The central angle is always twice the inscribed angle. Relationship to Thales’ Theorem
Refer to the above figure. If the two points A,B form a diameter of the circle, the inscribed angle will be 90°, which is Thales’ Theorem. You can verify this yourself by solving the formula above using an arc length of half the circumference of the circle.
You can also move the points A or B above until the inscribed angle is exactly 90°. You will see that the points A and B are then diametrically opposite each other.

Hope I helped!