An underwater diver sees the sun 47° above horizontal. How high is the sun above the horizon to a fisherman in
21.September, 2009
I need some help with this. I have tried and I keep getting 33.56 degrees. Thanks for the help.
Angles of incidence and refraction are measured from the vertical.
The diver sees the sun at 47deg. above horizontal. That is:
90 – 47
= 43 deg. to the vertical.
The fisherman sees the sun at x deg. above horizontal. That is:
90 – x deg. to the vertical.
Therefore:
sin(90 – x) / sin(43) = 1.33
cos(x) / sin(43) = 1.33
x = 24.90 deg.
21.September, 2009 um 1:04 pm
Angles of incidence and refraction are measured from the vertical.
The diver sees the sun at 47deg. above horizontal. That is:
90 – 47
= 43 deg. to the vertical.
The fisherman sees the sun at x deg. above horizontal. That is:
90 – x deg. to the vertical.
Therefore:
sin(90 – x) / sin(43) = 1.33
cos(x) / sin(43) = 1.33
x = 24.90 deg.
References :